Min Cute

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For a recent episode of SBS's Running Man, Jeon So Min participated in the show despite the recent worsening of her health condition, but she was ultimately rushed to the hospital in the middle of shooting.

  1. Jung So Min Cute Fairy
  2. Min Cute

The most recent episode starred guests, Ahn Bo Hyun, Lee Joo Young, Ji Lee Soo, and Song Jin Woo.

As one of the cast, Jeon So Min did her best to smile, but she looked pale and unwell from the beginning of the show.

She even did her best to show great reactions and participate in the show, but she had to step out in the middle of shooting and went straight to the hospital.

Following her disappearance from the episode, Yoo Jae Suk explained that Jeon So Min hadn't been feeling well.

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So Min hasn't been feeling well for a few days now. She immediately went to the hospital. We'll work really hard in hopes that So Min will get better soon.

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– Yoo Jae Suk

The other members also cheered Jeon So Min on with messages of support.

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Cheer up, So Min!

Have a safe trip to the hospital!

Don't worry about the filming!

– Running Man Cast

On April 2, Jeon So Min's agency announced that the actress would take a hiatus to focus on her recovery.

Jeon So Min will take a hiatus for around 1 month in order to recover her health. She plans to get some rest and focus on her recovery.

– Entertainment IAM

Get well soon, Jeon So Min!

A graph and two of its cuts. The dotted line in red represents a cut with three crossing edges. The dashed line in green represents one of the minimum cuts of this graph, crossing only two edges.[1]

In graph theory, a minimum cut or min-cut of a graph is a cut (a partition of the vertices of a graph into two disjoint subsets) that is minimal in some metric.

Variations of the minimum cut problem consider weighted graphs, directed graphs, terminals, and partitioning the vertices into more than two sets.

The weighted min-cut problem allowing both positive and negative weights can be trivially transformed into a weighted maximum cut problem by flipping the sign in all weights.

Without terminal nodes[edit]

Jung So Min Cute Fairy

Min Cute

About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators. Channel synthesizing tik tok videos about cute dogs.😍😍😍Subscribe to the channel to follow the next videos.😘😘😘Thank You for Watching Video 😍😍😍Donate.

– Yoo Jae Suk

The other members also cheered Jeon So Min on with messages of support.

Cheer up, So Min!

Have a safe trip to the hospital!

Don't worry about the filming!

– Running Man Cast

On April 2, Jeon So Min's agency announced that the actress would take a hiatus to focus on her recovery.

Jeon So Min will take a hiatus for around 1 month in order to recover her health. She plans to get some rest and focus on her recovery.

– Entertainment IAM

Get well soon, Jeon So Min!

A graph and two of its cuts. The dotted line in red represents a cut with three crossing edges. The dashed line in green represents one of the minimum cuts of this graph, crossing only two edges.[1]

In graph theory, a minimum cut or min-cut of a graph is a cut (a partition of the vertices of a graph into two disjoint subsets) that is minimal in some metric.

Variations of the minimum cut problem consider weighted graphs, directed graphs, terminals, and partitioning the vertices into more than two sets.

The weighted min-cut problem allowing both positive and negative weights can be trivially transformed into a weighted maximum cut problem by flipping the sign in all weights.

Without terminal nodes[edit]

Jung So Min Cute Fairy

The minimum cut problem in undirected, weighted graphs can be solved in polynomial time by the Stoer-Wagner algorithm. In the special case when the graph is unweighted, Karger's algorithm provides an efficient randomized method for finding the cut. In this case, the minimum cut equals the edge connectivity of the graph.

A generalization of the minimum cut problem without terminals is the minimum k-cut, in which the goal is to partition the graph into at least k connected components by removing as few edges as possible. For a fixed value of k, this problem can be solved in polynomial time, though the algorithm is not practical for large k. [2]

With terminal nodes[edit]

When two terminal nodes are given, they are typically referred to as the source and the sink. In a directed, weighted flow network, the minimum cut separates the source and sink vertices and minimizes the total weight on the edges that are directed from the source side of the cut to the sink side of the cut. As shown in the max-flow min-cut theorem, the weight of this cut equals the maximum amount of flow that can be sent from the source to the sink in the given network.

In a weighted, undirected network, it is possible to calculate the cut that separates a particular pair of vertices from each other and has minimum possible weight. A system of cuts that solves this problem for every possible vertex pair can be collected into a structure known as the Gomory–Hu tree of the graph.

A generalization of the minimum cut problem with terminals is the k-terminal cut, or multi-terminal cut. This problem is NP-hard, even for k=3{displaystyle k=3}.[3]

Applications[edit]

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Graph partition problems are a family of combinatorial optimization problems in which a graph is to be partitioned into two or more parts with additional constraints such as balancing the sizes of the two sides of the cut. Segmentation-based object categorization can be viewed as a specific case of normalized min-cut spectral clustering applied to image segmentation.

Due to max-flow min-cut theorem, 2 nodes' Minimum cut value is equal to their maxflow value. In this case, some algorithms used in maxflow problem could also be used to solve this question.

Number of minimum cuts[edit]

A graph with n{displaystyle n} vertices can at the most have (n2)=n(n−1)2{displaystyle {binom {n}{2}}={frac {n(n-1)}{2}}} distinct minimum cuts.This bound is tight in the sense that a (simple) cycle on n{displaystyle n} vertices has exactly n(n−1)2{displaystyle {frac {n(n-1)}{2}}} minimum cuts.

See also[edit]

  • Vertex separator, an analogous concept to minimum cuts for vertices instead of edges

References[edit]

  1. ^'4 Min-Cut Algorithms'.CS1 maint: discouraged parameter (link)
  2. ^'A Polynomial Algorithm for the k-cut Problem for Fixed k'.Cite journal requires |journal= (help)
  3. ^'The Complexity of Multiterminal Cuts'(PDF).Cite journal requires |journal= (help)
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